6.2

Transport in plants

Root hair cells, xylem and phloem and what each transports, transpiration and translocation, the factors that change the rate of water uptake and how to measure them, and how leaves are adapted for photosynthesis and for surviving extreme conditions.

About 22 minutes to read

6.8Plant tissues

Plant tissues include epidermal tissues, palisade mesophyll, spongy mesophyll, xylem and phloem, and meristem tissue found at the growing tips of shoots and roots.

The leaf is a plant organ, and you are expected to explain how the structures of plant tissues are related to their functions. Knowledge of the leaf is limited to the epidermis, palisade and spongy mesophyll, xylem and phloem, and the guard cells surrounding stomata — so there is a fixed list to learn, and nothing beyond it.

A cross-section of a leaf: epidermis top and bottom, palisade mesophyll, spongy mesophyll with air spaces, a vascular bundle of xylem and phloem, and stomata with guard cells.
Figure: Leaf tissues and what they are for

Practical skill

Observing and drawing a transverse section of a leaf

  1. Look at a prepared slide of a leaf section under the microscope, starting on the lowest power objective.
  2. Identify the layers from the top down: upper epidermis, palisade mesophyll, spongy mesophyll with its air spaces, lower epidermis and stomata.
  3. Draw with clear unbroken pencil lines, no shading, and label each tissue you can identify.
  4. Include a magnification scale, as with any biological drawing.

Watch out: The palisade layer is the one with the densely packed rectangular cells near the top surface. If your drawing shows the air spaces at the top and the packed cells underneath, the leaf is upside down.

Common mistake

Stomata are mostly on the lower surface, not the upper one. That keeps them out of direct sunlight, which reduces the rate of water loss — a common two-mark question.

Xylem
plant tissue that carries water and mineral ions upwards from the roots in the transpiration stream
Phloem
plant tissue that transports dissolved sugars from the leaves to the rest of the plant
Meristem tissue
plant tissue found at the growing tips of shoots and roots, where cells divide

6.7–6.10, 6.12–6.13Plant organ system

The roots, stem and leaves form a plant organ system for the transport of substances around the plant. Three cell types do the work, and each one is adapted to it.

Root hair cells are adapted for the efficient uptake of water by osmosis, and of mineral ions by active transport — the long thin extension gives a large surface area, and the many mitochondria supply the energy that active transport needs.

Xylem tissue transports water and mineral ions from the roots to the stems and leaves. It is composed of hollow tubes strengthened by lignin, adapted for the transport of water in the transpiration stream.

Phloem tissue transports dissolved sugars from the leaves to the rest of the plant for immediate use or storage. It is composed of tubes of elongated cells, and cell sap moves from one phloem cell to the next through pores in the end walls. The movement of food molecules through phloem tissue is called translocation.

Transpiration
The loss of water vapour from the leaves, which pulls water up through the xylem in the transpiration stream.
Translocation
The movement of dissolved sugars through phloem tissue, from the leaves to the rest of the plant.
Figure: Xylem and phloem compared

The role of stomata and guard cells is to control gas exchange and water loss. When the plant has plenty of water the guard cells swell and the stoma opens, letting carbon dioxide in for photosynthesis — and letting water vapour out. When water is short the guard cells become limp and the stoma closes, which protects the plant from wilting at the cost of stopping photosynthesis. That trade-off is the answer to most guard cell questions.

Four factors change the rate of transpiration, and each one works by changing how quickly water vapour leaves the stomata:

• Temperature. Warmer air means faster evaporation and faster diffusion, so a higher rate. • Humidity. Humid air already holds water vapour, so the concentration gradient out of the leaf is shallower and the rate falls. • Air movement. Wind blows away the water vapour gathered outside the stomata, keeping the gradient steep, so the rate rises. • Light intensity. Brighter light opens the stomata for photosynthesis, and open stomata lose more water.

Worked example

A plant loses 24 cm³ of water in 3 hours. Calculate the rate of transpiration in cm³ per hour, and predict what happens to it if a fan is switched on.

  1. Rate is a compound measure: amount ÷ time.
  2. 24 cm³ ÷ 3 hours = 8 cm³ per hour.
  3. A fan increases air movement, which carries away the water vapour outside the stomata.

Answer: 8 cm³ per hour, and the rate would increase — the steeper concentration gradient makes water vapour diffuse out of the stomata faster.

Data from these investigations has to be processed as well as collected. Translating information between numerical and graphical form is the commonest version of it: put the factor you chose on the x-axis and the rate on the y-axis, select scales for the axes that fill at least half the grid, plot each point with a small cross, and draw a line of best fit rather than joining the dots. Reading in the other direction — extract and interpret information from a graph, chart or table someone else made — means quoting actual figures with their units, not just saying the line goes up.

Practical skill

Measuring the rate of transpiration with a potometer

  1. Cut a leafy shoot under water and fit it into the potometer under water too, so no air enters the xylem.
  2. Dry the leaves, check the apparatus is airtight, and let the shoot settle for a few minutes.
  3. Introduce an air bubble into the capillary tube and record its starting position against the scale.
  4. Time how far the bubble moves in a set period — say five minutes — then reset it with the reservoir and repeat.
  5. Change one factor at a time: a fan for air movement, a lamp for light intensity, a bag over the shoot for humidity, or a water bath for temperature. Everything else stays the same.

Watch out: Repeat each condition at least three times and take a mean, because a single bubble reading is easily thrown off by a draught. And be precise about what you measured: the potometer measures water uptake, which is an estimate of transpiration, not transpiration itself.

Worked example

In a potometer the capillary tube has a radius of 0.5 mm. The air bubble moves 60 mm in 10 minutes. Calculate the volume of water taken up, and the rate in mm³ per minute.

  1. The water taken up fills a cylinder of the tube: volume = πr² × length.
  2. π × 0.5² × 60 = π × 0.25 × 60.
  3. = 47.1 mm³ (3 significant figures).
  4. Rate = volume ÷ time = 47.1 ÷ 10.

Answer: 47.1 mm³ taken up, a rate of 4.71 mm³ per minute.

Practical skill

Investigating the distribution of stomata and guard cells

  1. Paint a thin layer of clear nail varnish onto the lower surface of a leaf and let it dry.
  2. Peel the dried layer off with tweezers — it carries an impression of the surface, including the stomata.
  3. Mount it on a slide and view under the microscope on high power.
  4. Count the stomata in one field of view, then repeat for several different fields and for the upper surface too.
  5. Work out the area of the field of view so the counts can be converted into stomata per mm².

Watch out: Sample fairly: take several fields of view from different parts of the leaf rather than choosing the crowded ones, and use the same magnification throughout, or the counts cannot be compared.

Worked example

A student counts the stomata in five fields of view on the lower surface of a leaf: 12, 15, 11, 14 and 13. The field of view is a circle of diameter 0.5 mm. Calculate the mean count and the number of stomata per mm².

  1. Arithmetic mean = total ÷ number of readings = (12 + 15 + 11 + 14 + 13) ÷ 5 = 65 ÷ 5 = 13.
  2. Area of the field of view = πr², and r = diameter ÷ 2 = 0.25 mm.
  3. π × 0.25² = π × 0.0625 = 0.196 mm².
  4. Stomata per mm² = 13 ÷ 0.196.

Answer: A mean of 13 stomata per field of view, which is about 66 stomata per mm².

Five fields of view is a sample of the data, not a census, and the principles of sampling apply. The sample has to be large enough that one unusual patch of leaf does not decide the answer, and representative — taken from different parts of the leaf, and from different leaves if you are describing the plant rather than that one leaf. If a question asks why a result is unreliable, sample size and how the sample was chosen are the two places to look.

Figure: Transpiration rate at different humidities
Readings from a potometer with everything except humidity held constant.

Worked example

Using the table above: describe the relationship between humidity and the rate of water uptake, and calculate the percentage decrease in rate between 20% and 80% humidity.

  1. Describe the trend first, then quote figures from the table to support it.
  2. As humidity increases the rate of water uptake decreases, from 4.8 mm³/min at 20% to 0.4 mm³/min at 100%.
  3. Decrease between 20% and 80%: 4.8 − 1.5 = 3.3 mm³/min.
  4. Percentage decrease = (3.3 ÷ 4.8) × 100.

Answer: A negative relationship — higher humidity, lower rate — and a decrease of 69% between 20% and 80% humidity. The reason is the concentration gradient: humid air outside the leaf means less difference in water vapour concentration, so diffusion out of the stomata slows.

Common mistake

A potometer measures water uptake, not water loss. They are close but not the same — some water is used in photosynthesis and stays in the plant — so a careful answer says "uptake is used as an estimate of transpiration".

6.11B, 6.14BThe leaf, and plants in extreme environments

Biology only — not on the Combined Science specification

A leaf has two jobs that pull in opposite directions. It has to absorb as much light and carbon dioxide as possible, which means being wide, thin and open to the air; and it has to avoid drying out, which means being the opposite. Every adaptation of a leaf is a compromise between the two, and saying so is often what turns a description into an explanation.

Figure: Leaf structure and what each part is for

In a desert the compromise shifts decisively towards saving water. A cactus has leaves reduced to spines, so almost no surface is exposed and grazing animals are deterred; photosynthesis happens in the swollen green stem instead, which also stores water. The cuticle is thick, the stomata are few, sunken into pits and open only at night when the air is cooler, and the roots are shallow and spread widely to catch what little rain falls.

Marram grass on a sand dune faces the same problem for a different reason — constant wind and free-draining sand. Its leaves roll into a tube so that the stomata face inwards into a pocket of still, humid air; hairs around the stomata trap moisture, and the stomata themselves are sunken.

Common mistake

Every water-saving adaptation costs photosynthesis. A cactus with spines instead of leaves absorbs far less light than a broad-leaved plant would, and an answer that treats the adaptation as free has missed the trade-off the question is usually testing.

Before you practise

  • Xylem carries water and mineral ions up from the roots, in dead cells strengthened with lignin; phloem carries dissolved sugars in both directions, in living cells.
  • Transpiration is water loss from the leaves, which pulls the column of water up the xylem; translocation is the movement of sugars.
  • A root hair cell has a long extension, giving a large surface area for absorbing water and mineral ions.
  • Four factors raise the rate of water uptake: higher temperature, higher light intensity, more air movement, lower humidity.
  • Stomata are opened and closed by guard cells, trading carbon dioxide intake against water loss.
  • Every water-saving adaptation costs photosynthesis — name the trade-off.

Now practise it

Reading is the easy half. Answer questions on 6.2 Transport in plants and find out which parts you actually know.