4.1

Reactivity and extracting metals

The reactivity series and how it is worked out from reactions with water, acids and salt solutions, displacement as a redox reaction, and why the method used to extract a metal depends on where it sits in the series.

About 22 minutes to read

4.1, 4.3The reactivity series

When metals react with other substances the metal atoms form positive ions. The reactivity of a metal is related to its tendency to form positive ions — the more readily a metal loses its outer electrons, the more reactive it is.

Metals can be arranged in order of their reactivity in a reactivity series. The metals potassium, sodium, lithium, calcium, magnesium, zinc, iron and copper can be put in order of their reactivity from their reactions with water and dilute acids. The non-metals hydrogen and carbon are often included in the reactivity series.

Carbon and hydrogen are included because their positions decide how a metal can be extracted, and whether it reacts with acid.
Figure: Reactions with water and with dilute acid at room temperature
The reactions of metals with water and acids here are limited to room temperature and do not include reactions with steam.

You should be able to recall and describe the reactions, if any, of potassium, sodium, lithium, calcium, magnesium, zinc, iron and copper with water or dilute acids, and where appropriate place these metals in order of reactivity.

The two general equations are:

• metal + water → metal hydroxide + hydrogen • metal + acid → salt + hydrogen

You should also be able to explain how the reactivity of metals with water or dilute acids is related to the tendency of the metal to form its positive ion. Both reactions require the metal atom to lose electrons and become a positive ion, so a metal that loses electrons readily reacts vigorously, and one that does not — copper — does not react at all.

A more reactive metal can displace a less reactive metal from a compound. That gives a second way of ordering metals, and you should be able to deduce an order of reactivity of metals based on experimental results.

The more reactive metal takes the place of the less reactive one in the compound.

Worked example

Four metals W, X, Y and Z are tested. W and Y fizz in dilute acid but not in water; X fizzes in cold water; Z does nothing in either. W displaces Y from its sulfate solution. Deduce an order of reactivity.

  1. Reacting with cold water is the strongest evidence, so X is the most reactive.
  2. W and Y react with acid but not water, so both are below X.
  3. W displaces Y, so W is more reactive than Y.
  4. Z reacts with neither, so it is the least reactive.
  5. Assemble the order from the evidence, most reactive first.

Answer: X, W, Y, Z. Every step must be justified by an observation — deducing an order means quoting the evidence, not recalling the standard series.

Common mistake

Copper does not react with dilute acids, so "no observation" is a result, not a failed experiment. It places copper below hydrogen in the series.

Reactivity series
an order of metals by reactivity, determined by their reactions with water and dilute acids; the more readily a metal loses its outer electrons to form positive ions, the more reactive it is

4.2Oxidation and reduction in terms of electronsHigher tier

Oxidation is the loss of electrons and reduction is the gain of electrons.

This is the wider definition, and it applies to reactions where no oxygen is involved at all. The word OILRIG is the usual memory aid: Oxidation Is Loss, Reduction Is Gain — of electrons.

You should be able to write ionic equations for displacement reactions, and identify in a given reaction, symbol equation or half equation which species are oxidised and which are reduced.

An ionic equation for a displacement reaction leaves out the spectator ions — the ones that are in solution before and after and take no part.

Worked example

Zinc displaces copper from copper sulfate solution: Zn + CuSO₄ → ZnSO₄ + Cu. Write the ionic equation and say which species is oxidised.

  1. Write the ions present: Zn(s), Cu²⁺(aq), SO₄²⁻(aq), Zn²⁺(aq), Cu(s).
  2. The sulfate ion is unchanged on both sides, so it is a spectator ion and is left out.
  3. What remains is Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s).
  4. The zinc atom has become a 2+ ion, so it has lost two electrons — oxidation.
  5. The copper ion has become an atom, so it has gained two electrons — reduction.

Answer: Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s). Zinc is oxidised; copper ions are reduced.

Common mistake

Decide which species is oxidised by tracking the charge, not the appearance of the substance. Going from Zn to Zn²⁺ is a rise in charge, which means electrons were lost — oxidation — even though nothing burned and no oxygen was present.

Redox reaction
a reaction in which oxidation and reduction happen together, one species losing electrons while another gains them

4.5, 4.9Metal oxides

Metals react with oxygen to produce metal oxides. The reactions are oxidation reactions because the metals gain oxygen.

You should be able to explain reduction and oxidation in terms of loss or gain of oxygen. At this stage the definitions are simply:

• oxidation is the gain of oxygen • reduction is the loss of oxygen.

Both happen in the same reaction. When magnesium burns in air, 2Mg + O₂ → 2MgO, the magnesium is oxidised because it has gained oxygen — and the oxygen itself is not described as reduced here, because nothing has lost oxygen. It is in the extraction reactions below that the two appear together.

Oxidation
the gain of oxygen in a reaction; more widely, the loss of electrons
Reduction
the loss of oxygen in a reaction; more widely, the gain of electrons

4.4, 4.6–4.7Extraction of metals and reduction

Unreactive metals such as gold are found in the Earth as the metal itself, but most metals are found as compounds that require chemical reactions to extract the metal.

Metals less reactive than carbon can be extracted from their oxides by reduction with carbon. Reduction involves the loss of oxygen.

Knowledge and understanding are limited to the reduction of oxides using carbon, and knowledge of the details of the processes used in the extraction of metals is not required.

Carbon's position in the reactivity series decides which metals can be extracted this way: only those below it.

You should be able to identify the substances which are oxidised or reduced in terms of gain or loss of oxygen, and interpret or evaluate specific metal extraction processes when given appropriate information.

In ZnO + C → Zn + CO, the zinc oxide has lost oxygen so it has been reduced, and the carbon has gained oxygen so it has been oxidised. Both happen at once, which is why these are called redox reactions.

Worked example

Explain why aluminium cannot be extracted by heating its oxide with carbon, but iron can.

  1. Reduction with carbon works only for metals less reactive than carbon.
  2. Aluminium is above carbon in the reactivity series.
  3. So carbon cannot take the oxygen away from aluminium oxide — aluminium holds its oxygen more strongly.
  4. Iron is below carbon in the series, so carbon can remove the oxygen from iron oxide.

Answer: Aluminium is more reactive than carbon, so carbon cannot reduce its oxide; iron is less reactive than carbon, so it can be. Aluminium must be extracted by electrolysis instead.

4.7Using electrolysis to extract metals

Metals can be extracted from molten compounds using electrolysis. Electrolysis is used if the metal is too reactive to be extracted by reduction with carbon, or if the metal reacts with carbon.

Large amounts of energy are used in the extraction process, both to melt the compounds and to produce the electrical current — which is why electrolysis is the expensive option, and why it is used only when reduction with carbon will not work.

Aluminium is manufactured by the electrolysis of a molten mixture of aluminium oxide and cryolite, using carbon as the positive electrode (anode).

You should be able to explain why a mixture is used as the electrolyte, and why the positive electrode must be continually replaced.

Why a mixture: aluminium oxide has a very high melting point on its own. Dissolving it in molten cryolite lowers the melting point of the mixture, so less energy — and less money — is needed to keep the electrolyte molten.

Why the anode is replaced: oxygen is produced at the positive electrode, which is made of carbon. At the high temperature of the cell, that oxygen reacts with the carbon to form carbon dioxide, so the anode gradually burns away and must be replaced.

Common mistake

Cryolite lowers the melting point; it is not there to make the mixture conduct better or to react with the aluminium. Say what it does and why that saves energy.

Extraction by electrolysis
extracting a metal from its molten compound using electrolysis, used where the metal is too reactive to be extracted by reduction with carbon, or reacts with carbon

4.8Alternative methods of extracting metalsHigher tier

The Earth's resources of metal ores are limited.

Copper ores are becoming scarce, and new ways of extracting copper from low-grade ores include phytomining and bioleaching. These methods avoid traditional mining methods of digging, moving and disposing of large amounts of rock.

Phytomining uses plants to absorb metal compounds. The plants are harvested and then burned to produce ash that contains metal compounds.

Bioleaching uses bacteria to produce leachate solutions that contain metal compounds.

The metal compounds can be processed to obtain the metal. For example, copper can be obtained from solutions of copper compounds by displacement using scrap iron, or by electrolysis.

You should be able to evaluate alternative biological methods of metal extraction, given appropriate information.

The advantages are that these methods work on low-grade ores that would not be worth mining conventionally, they avoid digging, moving and disposing of large amounts of rock, and they use less energy. The disadvantages are that both are slow — phytomining takes a growing season or more — and the metal compounds still have to be processed afterwards, which itself costs energy.

Worked example

Explain why copper can be obtained from a solution of copper sulfate using scrap iron, and write the ionic equation.

  1. Iron is more reactive than copper.
  2. A more reactive metal displaces a less reactive metal from a solution of its compound, so the iron displaces the copper.
  3. The iron atoms lose electrons and the copper ions gain them.
  4. Scrap iron is used because it is cheap — the value is in the copper recovered.

Answer: Fe(s) + Cu²⁺(aq) → Fe²⁺(aq) + Cu(s). Iron is oxidised and the copper ions are reduced.

Phytomining
a method of extracting metals in which plants absorb metal compounds, are harvested and then burned to produce ash containing those compounds
Bioleaching
a method of extracting metals in which bacteria produce leachate solutions containing metal compounds

Before you practise

  • The order runs potassium, sodium, calcium, magnesium, aluminium, (carbon), zinc, iron, (hydrogen), copper, silver, gold.
  • A more reactive metal displaces a less reactive one from its compound.
  • Displacement is redox: the metal that is displaced gains electrons and is reduced, the one that displaces it loses them and is oxidised.
  • Oxidation is gain of oxygen and reduction is loss of oxygen — the same reaction, described a second way.
  • Metals above carbon are extracted by electrolysis; metals below it are reduced by heating with carbon.
  • Gold and other very unreactive metals are found in the Earth as the metal itself.
  • Electrolysis is expensive because melting the ore and running the current both take large amounts of energy.
  • Phytomining and bioleaching extract copper from low-grade ores — cheaper and less damaging, but slow.

Now practise it

Reading is the easy half. Answer questions on 4.1 Reactivity and extracting metals and find out which parts you actually know.