5.4

Gas volumes and the mole

The molar volume of a gas at room temperature and pressure, and using it with balanced equations and Avogadro's law to work out the volumes of gases in a reaction.

About 9 minutes to read

5.16CVolumes of gasesHigher tier

Chemistry only, and Higher tier only — not on the Combined Science specification

Equal amounts in moles of gases occupy the same volume under the same conditions of temperature and pressure.

That is a stronger statement than it looks. It does not matter which gas it is: one mole of hydrogen and one mole of carbon dioxide take up the same volume, even though one weighs 2 g and the other 44 g. In a gas the particles are so far apart that the size of the particle makes almost no difference to the space the gas fills.

The volume of one mole of any gas at room temperature and pressure — 20 °C and 1 atmosphere pressure — is 24 dm³.

One mole of any gas fills 24 dm³ at room temperature and pressure, whatever the gas.

That gives one relationship to learn, and two rearrangements of it:

volume in dm³ = moles × 24 moles = volume in dm³ ÷ 24

You should be able to change the subject of a mathematical equation, and to substitute numerical values into algebraic equations using appropriate units for physical quantities — so be ready to use it either way round.

Worked example

Calculate the volume of 8.0 g of oxygen gas at room temperature and pressure. (Ar of O = 16.)

  1. Oxygen gas is O₂, so its Mr = 2 × 16 = 32.
  2. moles = mass ÷ Mr = 8.0 ÷ 32 = 0.25 mol.
  3. volume = moles × 24 = 0.25 × 24.
  4. Give the unit: the molar volume is in dm³, so the answer is in dm³.

Answer: 6.0 dm³

Common mistake

Use the formula of the gas as it exists. Oxygen, hydrogen, nitrogen and chlorine are all diatomic — O₂, H₂, N₂, Cl₂ — so dividing by the atomic mass instead of the molecular mass doubles the number of moles and doubles the volume.

Molar gas volume
the volume occupied by one mole of any gas; equal amounts in moles of gases occupy the same volume under the same conditions of temperature and pressure

5.17C–5.18CGas volumes from equationsHigher tier

Chemistry only, and Higher tier only — not on the Combined Science specification

The volumes of gaseous reactants and products can be calculated from the balanced equation for the reaction.

You should be able to:

• calculate the volume of a gas at room temperature and pressure from its mass and relative formula mass • calculate volumes of gaseous reactants and products from a balanced equation and a given volume of a gaseous reactant or product.

The second is quicker than it looks. Because equal moles of any gas occupy equal volumes, the mole ratio in the equation is also the volume ratio — as long as every substance being compared is a gas at the same temperature and pressure. There is no need to convert to moles and back.

Worked example

N₂ + 3H₂ → 2NH₃. What volume of ammonia is made from 60 cm³ of nitrogen, with hydrogen in excess, at the same temperature and pressure?

  1. All three substances are gases at the same conditions, so the mole ratio is also the volume ratio.
  2. The ratio of nitrogen to ammonia in the equation is 1 : 2.
  3. So the volume of ammonia is twice the volume of nitrogen.
  4. 2 × 60 cm³ = 120 cm³. No conversion to moles is needed.

Answer: 120 cm³ of ammonia

Worked example

CaCO₃ → CaO + CO₂. Calculate the volume of carbon dioxide produced at room temperature and pressure when 5.0 g of calcium carbonate decomposes completely. (Mr of CaCO₃ = 100.)

  1. Here the reactant is a solid, so the volume shortcut does not apply — go through moles.
  2. moles of CaCO₃ = 5.0 ÷ 100 = 0.050 mol.
  3. The ratio in the equation is 1 : 1, so moles of CO₂ = 0.050 mol.
  4. volume = moles × 24 = 0.050 × 24 = 1.2 dm³.
  5. If cm³ are wanted, multiply by 1000: 1200 cm³.

Answer: 1.2 dm³, or 1200 cm³, of carbon dioxide

Common mistake

The volume ratio shortcut only works between gases. If a solid or a solution appears in the comparison, as in the second example, you must convert to moles first.

Before you practise

  • One mole of any gas occupies the same volume at the same temperature and pressure — 24 dm³, or 24 000 cm³, at room temperature and pressure.
  • volume = moles × 24 dm³, and moles = volume ÷ 24.
  • Which gas it is makes no difference to the volume, only to the mass.
  • For a gas-to-gas question, the volume ratio is the mole ratio straight from the equation — no conversion is needed.
  • For a solid-to-gas question, go mass → moles → ratio → moles of gas → volume.
  • Check the units the question wants: dm³ or cm³, and convert by 1000.

Now practise it

Reading is the easy half. Answer questions on 5.4 Gas volumes and the mole and find out which parts you actually know.