7.1

Rates of reaction

Measuring a rate and reading it off a graph, the factors that change it explained by collision theory, and what a catalyst does — including the enzymes used in brewing.

About 20 minutes to read

7.1–7.2, 7.5Calculating rates of reactions

The rate of a chemical reaction can be found by measuring the quantity of a reactant used, or the quantity of product formed, over time:

mean rate of reaction = quantity of reactant used ÷ time taken mean rate of reaction = quantity of product formed ÷ time taken

The quantity of reactant or product can be measured by the mass in grams or by a volume in cm³, so the units of rate of reaction may be given as g/s or cm³/s. For the Higher tier you are also required to use quantity of reactants in terms of moles, and units for rate of reaction in mol/s.

Worked example

48 cm³ of gas is collected in 40 s. Calculate the mean rate of reaction.

  1. Identify the quantity: 48 cm³ of product formed.
  2. Identify the time: 40 s.
  3. mean rate = quantity ÷ time = 48 ÷ 40.
  4. Take the units from the quantities used: cm³ divided by s.

Answer: 1.2 cm³/s

You should be able to draw, and interpret, graphs showing the quantity of product formed or quantity of reactant used up against time.

These graphs have a characteristic shape. They are steepest at the start, when the reactants are most concentrated, and flatten as the reaction proceeds. When the line becomes horizontal the reaction has finished — no more product is being formed — and the height of that flat section shows the total amount of product made.

The slope of a tangent drawn to the curve gives the rate at that particular moment.

You should be able to draw tangents to the curves on these graphs and use the slope of the tangent as a measure of the rate of reaction.

The difference between the two rates is worth being clear about. The mean rate over a period is the total quantity divided by the total time — a single number for the whole run. The rate at a specific time is given by the slope of the tangent at that point on the curve, and it changes throughout the reaction: steep at the start, shallow near the end.

Rate of reaction
the quantity of reactant used or product formed divided by the time taken, with units such as g/s, cm³/s or mol/s

7.5Calculating the gradient of a tangentHigher tier

Higher tier students are also required to use quantity of reactants in terms of moles, and units for rate of reaction in mol/s, and should be able to calculate the gradient of a tangent to the curve on these graphs as a measure of rate of reaction at a specific time.

Calculating the gradient, rather than only describing the slope, is what separates the Higher tier requirement from the Foundation one. Draw the tangent so that it just touches the curve at the time asked for, extend it well across the graph, then take a large triangle from the tangent itself.

Worked example

A tangent drawn to a volume-time curve at 30 s passes through the points (10 s, 12 cm³) and (50 s, 44 cm³). Calculate the rate of reaction at 30 s.

  1. The gradient of the tangent is the rate at that moment.
  2. Change in volume = 44 − 12 = 32 cm³.
  3. Change in time = 50 − 10 = 40 s.
  4. gradient = 32 ÷ 40.
  5. Take the units from the axes: cm³ per s.

Answer: 0.8 cm³/s at 30 s

Common mistake

Read the triangle for the gradient off the tangent, not off the curve. Using two points on the curve itself gives an average across that interval, which is smaller than the true rate at the start of it.

7.3Collision theory and activation energy

Collision theory explains how various factors affect rates of reactions. According to this theory, chemical reactions can occur only when reacting particles collide with each other and with sufficient energy. The minimum amount of energy that particles must have to react is called the activation energy.

Increasing the concentration of reactants in solution, the pressure of reacting gases, and the surface area of solid reactants increases the frequency of collisions, and so increases the rate of reaction.

Increasing the temperature increases the frequency of collisions and makes the collisions more energetic, and so increases the rate of reaction.

A collision only causes a reaction if the particles meet with at least the activation energy.
Figure: Each factor explained by collision theory
Only temperature changes the energy of the collisions; the other three change only how often they happen.

You should be able to predict and explain, using collision theory, the effects of changing conditions of concentration, pressure and temperature on the rate of a reaction, and to predict and explain the effects of changes in the size of pieces of a reacting solid in terms of surface area to volume ratio.

Breaking a solid into smaller pieces does not change how much there is, but it increases the surface area to volume ratio — more of the substance is exposed where collisions can happen — so powdered marble reacts far faster with acid than a single lump of the same mass.

You should also be able to use simple ideas about proportionality when using collision theory to explain the effect of a factor on the rate of a reaction. If doubling the concentration doubles the frequency of collisions, then it doubles the rate — so a graph of rate against concentration is a straight line through the origin. Being able to say "twice as many particles, so twice as many collisions per second, so twice the rate" is what proportionality means here.

Common mistake

Increasing the concentration does not give the particles more energy. It makes collisions more frequent, not more energetic. Only raising the temperature does both.

Collision theory
the theory that chemical reactions can occur only when reacting particles collide with each other and with sufficient energy; increasing concentration, pressure or surface area increases the frequency of collisions

7.4Factors which affect the rates of chemical reactions

Factors which affect the rates of chemical reactions include: the concentrations of reactants in solution, the pressure of reacting gases, the surface area of solid reactants, the temperature, and the presence of catalysts.

You should be able to recall how changing these factors affects the rate of chemical reactions. Increasing any of the first four increases the rate, and adding a catalyst increases it too.

Required practical 5

Investigate how changes in concentration affect the rates of reactions

  1. State a hypothesis, for example that the rate of reaction is proportional to the concentration of the acid.
  2. Method 1, gas volume: react magnesium ribbon with dilute hydrochloric acid in a flask connected to a gas syringe. Record the volume of hydrogen every 10 s until the reaction stops.
  3. Repeat method 1 with several concentrations of acid, keeping the volume of acid, the mass and surface of the magnesium, and the temperature the same.
  4. Method 2, turbidity: mix sodium thiosulfate solution with dilute hydrochloric acid in a conical flask standing over a printed cross. Time how long the cross takes to disappear as the sulfur clouds the mixture.
  5. Repeat method 2 with several concentrations of thiosulfate, keeping the total volume, the temperature and the observer the same.

Common mistake

In the turbidity method, judging when the cross disappears is subjective. Keep the same person judging every run, view from the same height, and use the same flask and printed cross, or the comparison is not fair.

7.6–7.8Catalysts

Catalysts change the rate of chemical reactions but are not used up during the reaction. Different reactions need different catalysts. Enzymes act as catalysts in biological systems.

Catalysts increase the rate of reaction by providing a different pathway for the reaction that has a lower activation energy.

The catalysed pathway has a lower peak; the reactant and product levels — and so the overall energy change — are unchanged.

You should be able to explain catalytic action in terms of activation energy. The chain of reasoning is: the catalyst provides a different pathway with a lower activation energy, so a greater proportion of the colliding particles have enough energy to react, so more collisions are successful and the rate increases.

You should also be able to identify catalysts in reactions from their effect on the rate of reaction, and because they are not included in the chemical equation for the reaction. A substance that speeds the reaction up but appears on neither side of the equation, and can be recovered unchanged at the end, is a catalyst. You do not need to know the names of catalysts other than those specified in the subject content.

Common mistake

A catalyst does not lower the activation energy of the original reaction — it provides an alternative pathway that has a lower activation energy. It also has no effect on the overall energy change, so the reactant and product levels on a reaction profile stay exactly where they were.

Catalyst
a substance that increases the rate of a reaction without being used up, by providing a different pathway with a lower activation energy

Before you practise

  • rate = amount of reactant used or product formed ÷ time taken, with the unit that follows from those quantities.
  • Two ways to follow a reaction: measure the volume of gas given off, or the loss in mass, against time.
  • The mean rate is the whole change over the whole time; the rate at an instant is the gradient of the tangent at that point.
  • A reaction is fastest at the start, where the concentrations are highest, and the graph levels off when a reactant runs out.
  • Collision theory: a reaction happens when particles collide with at least the activation energy.
  • Higher temperature means more frequent collisions AND more energetic ones — both halves are needed for the mark.
  • Higher concentration or pressure means more particles in the same volume, so more frequent collisions. A powder has a larger surface area, so more of it is exposed.
  • A catalyst provides a different pathway with a lower activation energy; it is not used up and does not change the products.

Now practise it

Reading is the easy half. Answer questions on 7.1 Rates of reaction and find out which parts you actually know.